funcprog: Added week 3, assignment 7.

parent cc571c55
(* Alias for Printf.printf, because it saves typing characters. *)
let print = Printf.printf;;
(* 1: nth yields the N-th element of the list L, counting from zero. *)
let rec nth l n = match l with
| [] -> raise (Failure "Index out of bounds")
| h::t -> if n == 0 then h else nth t (n - 1)
;;
print "7.1: %b\n" ((=) (nth [1;2;3] 2) 3 );;
open List
(* 2: Given a list of non-empty lists L, head yields the list of first elements
* of the sublists. *)
let heads l = map hd l;;
print "7.2: %b\n" ((=) (heads [[1;2;3];[4;5;6]]) [1;4]);;
(* 3: zip L M that given a pair of lists yields the list of pairs of elements
* from corresponding list positions. If the length of one argument list
* exceeds * the length of the other, surplus elements are to be ignored. *)
let rec zip ?(s=[]) l1 l2 = match (l1, l2) with
| [], _ -> s (* If the first list is empty, return list. *)
| _, [] -> s (* If the second list is empty, return list. *)
(* Take the head and tail of both lists. Then call zip with the list,
* and append a tuple of the two heads to it. The last two arguments
* of zip are the tails of both lists. *)
| h1::t1, h2::t2 -> zip ~s:(s @ [h1, h2]) t1 t2
;;
print "7.3: %b\n" ((=) (zip [1;2;3] [true;false]) [(1,true);(2,false)]);;
(* 4: map f l that given a function F applies it to every element of list L
* returning a list of the results. *)
let rec map f l = match l with
| [] -> []
| h::t -> f h::map f t
;;
let inc n = 1 + n in
print "7.4: %b\n" ((=) (map inc [1;2;3;4;5]) [2;3;4;5;6]);;
(* 5: reduce f z l that given a function f, a begin element z and a list l
* applies f to z and the first element of l, then applies f to the result of
* this application and the second element of l, etc. Which means that reduce f
* z [a;b;c] becomes f (f (f z a) b) c. *)
let rec reduce f z l = match l with
| [] -> z
| h::t -> reduce f (f z h) t
;;
print "7.5: %b\n" ((=) (reduce (+) 0 [1;2;3;4;5]) 15);;
(* 6: isSublist l s that checks whether or not the argument list s is a sublist
* of the argument list l. *)
let rec isSublist l s = match (l, s) with
| _, [] -> true
| [], _ -> false
| h1::t1, h2::t2 ->
(* if the head of s matches the head of l'. *)
h1 = h2
(* and the next head of s matches the next head of l. *)
&& ( t1 = [] && t2 = [] || hd t1 = hd t2 )
(* recursively match the tails of s and l. *)
&& isSublist t1 t2
(* otherwise, continue with the tail of s. *)
|| isSublist t1 s
;;
print "7.6.1: %b\n" (isSublist [1;2;3;4] [3;4]);;
print "7.6.2: %b (%s)\n" (isSublist [1;2;3;4] [2;4]) "expected failure";;
print "7.6.3: %b\n" (isSublist [] []);;
(* 7. lookup l key that given a list l of (key, value) tuples and a key returns
* the value associated with that key. *)
let rec lookup l key = match l with
| [] -> raise (Failure "Key not found")
| h::t -> let k,v = h in if key = k then v else lookup t key
;;
print "7.7: %b\n" ((=) (lookup [(1,"foo");(2,"bar");(3,"baz")] 2) "bar");;
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