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Taddeüs Kroes
uva
Commits
7ce81fae
Commit
7ce81fae
authored
Nov 22, 2011
by
Sander Mathijs van Veen
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funcprog: Added week 3, assignment 7.
parent
cc571c55
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7ce81fae
(* Alias for Printf.printf, because it saves typing characters. *)
let
print
=
Printf
.
printf
;;
(* 1: nth yields the N-th element of the list L, counting from zero. *)
let
rec
nth
l
n
=
match
l
with
|
[]
->
raise
(
Failure
"Index out of bounds"
)
|
h
::
t
->
if
n
==
0
then
h
else
nth
t
(
n
-
1
)
;;
print
"7.1: %b
\n
"
((
=
)
(
nth
[
1
;
2
;
3
]
2
)
3
);;
open
List
(* 2: Given a list of non-empty lists L, head yields the list of first elements
* of the sublists. *)
let
heads
l
=
map
hd
l
;;
print
"7.2: %b
\n
"
((
=
)
(
heads
[[
1
;
2
;
3
];[
4
;
5
;
6
]])
[
1
;
4
]);;
(* 3: zip L M that given a pair of lists yields the list of pairs of elements
* from corresponding list positions. If the length of one argument list
* exceeds * the length of the other, surplus elements are to be ignored. *)
let
rec
zip
?
(
s
=
[]
)
l1
l2
=
match
(
l1
,
l2
)
with
|
[]
,
_
->
s
(* If the first list is empty, return list. *)
|
_
,
[]
->
s
(* If the second list is empty, return list. *)
(* Take the head and tail of both lists. Then call zip with the list,
* and append a tuple of the two heads to it. The last two arguments
* of zip are the tails of both lists. *)
|
h1
::
t1
,
h2
::
t2
->
zip
~
s
:
(
s
@
[
h1
,
h2
])
t1
t2
;;
print
"7.3: %b
\n
"
((
=
)
(
zip
[
1
;
2
;
3
]
[
true
;
false
])
[(
1
,
true
);(
2
,
false
)]);;
(* 4: map f l that given a function F applies it to every element of list L
* returning a list of the results. *)
let
rec
map
f
l
=
match
l
with
|
[]
->
[]
|
h
::
t
->
f
h
::
map
f
t
;;
let
inc
n
=
1
+
n
in
print
"7.4: %b
\n
"
((
=
)
(
map
inc
[
1
;
2
;
3
;
4
;
5
])
[
2
;
3
;
4
;
5
;
6
]);;
(* 5: reduce f z l that given a function f, a begin element z and a list l
* applies f to z and the first element of l, then applies f to the result of
* this application and the second element of l, etc. Which means that reduce f
* z [a;b;c] becomes f (f (f z a) b) c. *)
let
rec
reduce
f
z
l
=
match
l
with
|
[]
->
z
|
h
::
t
->
reduce
f
(
f
z
h
)
t
;;
print
"7.5: %b
\n
"
((
=
)
(
reduce
(
+
)
0
[
1
;
2
;
3
;
4
;
5
])
15
);;
(* 6: isSublist l s that checks whether or not the argument list s is a sublist
* of the argument list l. *)
let
rec
isSublist
l
s
=
match
(
l
,
s
)
with
|
_
,
[]
->
true
|
[]
,
_
->
false
|
h1
::
t1
,
h2
::
t2
->
(* if the head of s matches the head of l'. *)
h1
=
h2
(* and the next head of s matches the next head of l. *)
&&
(
t1
=
[]
&&
t2
=
[]
||
hd
t1
=
hd
t2
)
(* recursively match the tails of s and l. *)
&&
isSublist
t1
t2
(* otherwise, continue with the tail of s. *)
||
isSublist
t1
s
;;
print
"7.6.1: %b
\n
"
(
isSublist
[
1
;
2
;
3
;
4
]
[
3
;
4
]);;
print
"7.6.2: %b (%s)
\n
"
(
isSublist
[
1
;
2
;
3
;
4
]
[
2
;
4
])
"expected failure"
;;
print
"7.6.3: %b
\n
"
(
isSublist
[]
[]
);;
(* 7. lookup l key that given a list l of (key, value) tuples and a key returns
* the value associated with that key. *)
let
rec
lookup
l
key
=
match
l
with
|
[]
->
raise
(
Failure
"Key not found"
)
|
h
::
t
->
let
k
,
v
=
h
in
if
key
=
k
then
v
else
lookup
t
key
;;
print
"7.7: %b
\n
"
((
=
)
(
lookup
[(
1
,
"foo"
);(
2
,
"bar"
);(
3
,
"baz"
)]
2
)
"bar"
);;
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