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- # vim: set fileencoding=utf-8 :
- - Fix BisonSyntaxError location tracking.
- - Sort polynom by its exponents?
- - Fix division by zero caused by "0/0": Catch exception in front-end
- smvv@multivac ~/work/trs $ printf "a/0\n??" | ./main.py
- Traceback (most recent call last):
- File "./main.py", line 75, in <module>
- main()
- File "./main.py", line 64, in main
- node = p.run(debug=args.debug)
- File "/home/smvv/work/trs/external/pybison/src/python/bison.py", line 258, in run
- self.report_last_error(filename, e)
- File "/home/smvv/work/trs/external/pybison/src/python/bison.py", line 251, in run
- self.engine.runEngine(debug)
- File "bison_.pyx", line 592, in bison_.ParserEngine.runEngine (build/external/pybison/bison_.c:592)
- File "/home/smvv/work/trs/src/parser.py", line 195, in hook_handler
- possibilities = handler(retval)
- File "/home/smvv/work/trs/src/rules/fractions.py", line 23, in match_constant_division
- raise ZeroDivisionError('Division by zero: %s.' % node)
- ZeroDivisionError: Division by zero: a / 0.
- smvv@multivac ~/work/trs $ printf "0/0\n??" | ./main.py
- Traceback (most recent call last):
- File "./main.py", line 75, in <module>
- main()
- File "./main.py", line 64, in main
- node = p.run(debug=args.debug)
- File "/home/smvv/work/trs/external/pybison/src/python/bison.py", line 258, in run
- self.report_last_error(filename, e)
- File "/home/smvv/work/trs/external/pybison/src/python/bison.py", line 251, in run
- self.engine.runEngine(debug)
- File "bison_.pyx", line 592, in bison_.ParserEngine.runEngine (build/external/pybison/bison_.c:592)
- File "/home/smvv/work/trs/src/parser.py", line 195, in hook_handler
- possibilities = handler(retval)
- File "/home/smvv/work/trs/src/rules/numerics.py", line 73, in match_divide_numerics
- divide = not divmod(n.value, dv)[1]
- ZeroDivisionError: integer division or modulo by zero
- - Last possibilities reduce to a similar result.
- smvv@multivac ~/work/trs $ printf "0/1\n??" | ./main.py
- <Possibility root="0 / 1" handler=divide_numerics args=(0, 1)>
- Division of 0 by 1 reduces to 0.
- Division of 0 by 1 reduces to 0.
- - ExpressionNode.equals() werkend maken voor alle cases (negatie).
- - validation: preorder traversal implementatie vergelijken met andere
- implementaties.
- - No matches for sin(pi), sin(2pi), sin(4pi), etc...
- - Create unit tests for node inequivalence operator.
- - Line printer: 1 / (n + n)x -> 1 / (n + n) * x
- - Parser: 'apia' -> 'aa'
- - Unit tests for strategy.
- - Parser: add unit tests for operator associativity (derivatives/integrals).
- - Modules:
- + Equations with substitution
- + Sort
- + Gonio
- - Add parentheses to integral bounds where needed:
- int_(-1)^2 ... dx
- or, fix parser error using the following notation:
- int_-1^2 ... dx
- - Base hint selection on the desired final expression.
- To generate a hint for expression list A, ..., B:
- 1. Create a possibility tree for A.
- 2. Validate all expressions up to B:
- set ROOT = A
- for each expression C in <A, B] do:
- if final answer of C is not equal to final answer of A:
- validation failes at c
- find C in the possibility tree, traversing from ROOT
- if not found:
- validation continues, but generate an efficiency warning at C
- # FIXME: validation fails at C?
- set ROOT = C
- 3. Generate a hint:
- # ROOT should now be equal to B, so lookup of B is unnecessary
- set N = empty dictionary
- for each possibility of ROOT P node do:
- evaluate P(B) until the final expression of A is reached
- set N[P] = the number of explicit possibilities that have been applied in the evaluation
- the hint is that P for which the value of N[P] the smallest
- - Optimization: put possibility tree in hashmap: {'expression': [(handler, args, 'applied_expression')], ...}
- This hashmap can be used to speedup the calculation of possbility trees.
- - Fix: int -cf(x) dx (caused infinite loop)
- - Idea for validation that is not really working ATM:
- When validating that a => b:
- Apply reductions to a to obtain A, this costs N steps.
- Apply reductions to b to obtain B, this costs M steps.
- if A != B, validation fails (return status 0)
- else if M >= N, the uses has done a useless or bad step (return status 1)
- otherwise (if M < N), the user has reduced the expression correctly (return status 2)
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