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Taddeüs Kroes
trs
Commits
6b90f930
Commit
6b90f930
authored
Jan 08, 2012
by
Taddeus Kroes
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Forgot to add numerics rule file in earlier commits (A).
parent
6097dce7
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src/rules/numerics.py
src/rules/numerics.py
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src/rules/numerics.py
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6b90f930
from
..node
import
ExpressionLeaf
as
Leaf
,
TYPE_INTEGER
,
TYPE_FLOAT
,
OP_DIV
from
..possibilities
import
Possibility
as
P
from
.utils
import
nary_node
def
match_divide_numerics
(
node
):
"""
Combine two constants to a single constant in a division, if it does not
lead to a decrease in precision.
Example:
6 / 2 -> 3
3 / 2 -> 3 / 2 # 1.5 would mean a decrease in precision
3.0 / 2 -> 1.5
3 / 2.0 -> 1.5
3.0 / 2.0 -> 1.5
3 / 1.0 -> 3 # Exceptional case: division of integer by 1.0 keeps
# integer precision
"""
assert
node
.
is_op
(
OP_DIV
)
n
,
d
=
node
n_int
=
n
.
type
==
TYPE_INTEGER
n_float
=
n
.
type
==
TYPE_FLOAT
d_int
=
d
.
type
==
TYPE_INTEGER
d_float
=
d
.
type
==
TYPE_FLOAT
nv
,
dv
=
n
.
value
,
d
.
value
divide
=
False
if
n_int
and
d_int
:
# 6 / 2 -> 3
# 3 / 2 -> 3 / 2
divide
=
not
divmod
(
nv
,
dv
)[
1
]
else
:
if
d_float
and
dv
==
1.0
:
# 3 / 1.0 -> 3
dv
=
1
# 3.0 / 2 -> 1.5
# 3 / 2.0 -> 1.5
# 3.0 / 2.0 -> 1.5
divide
=
True
return
[
P
(
node
,
divide_numerics
,
(
nv
,
dv
))]
if
divide
else
[]
def
divide_numerics
(
root
,
args
):
"""
Combine two constants to a single constant in a division.
Examples:
6 / 2 -> 3
3.0 / 2 -> 1.5
3 / 2.0 -> 1.5
3.0 / 2.0 -> 1.5
3 / 1.0 -> 3
"""
n
,
d
=
args
return
Leaf
(
n
/
d
)
def
add_numerics
(
root
,
args
):
"""
Combine two constants to a single constant in an n-ary plus.
Example:
2 + 3 -> 5
"""
n0
,
n1
,
c0
,
c1
=
args
scope
=
root
.
get_scope
()
# Replace the left node with the new expression
scope
[
scope
.
index
(
n0
)]
=
Leaf
(
c0
+
c1
)
# Remove the right node
scope
.
remove
(
n1
)
return
nary_node
(
'+'
,
scope
)
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