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Taddeüs Kroes
trs
Commits
6503a97a
Commit
6503a97a
authored
Mar 14, 2012
by
Sander Mathijs van Veen
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Solved preprocessor inserting multiplication signs in keywords.
parent
3d713049
Changes
2
Show whitespace changes
Inline
Side-by-side
Showing
2 changed files
with
29 additions
and
18 deletions
+29
-18
src/parser.py
src/parser.py
+27
-17
tests/test_parser.py
tests/test_parser.py
+2
-1
No files found.
src/parser.py
View file @
6503a97a
...
...
@@ -141,6 +141,10 @@ class Parser(BisonParser):
import
re
# Replace known keywords with escape sequences.
for
i
,
keyword
in
enumerate
(
Parser
.
words
):
data
=
re
.
sub
(
keyword
,
chr
(
i
),
data
,
flags
=
re
.
I
)
# TODO: remove this quick preprocessing hack. This hack enables
# concatenated expressions, since the grammar currently does not
# support those. This workaround will replace:
...
...
@@ -151,20 +155,24 @@ class Parser(BisonParser):
# - "4a" with "4*a".
# - "a4" with "a^4".
pattern
=
(
'(?:(
\
))
\
s*(
\
()
'
# match: )( result: ) * (
+ '
|
([
a
-
z0
-
9
])
\
s
*
(
\
()
' # match: a( result: a * (
+ '
|
(
\
))
\
s
*
([
a
-
z0
-
9
])
' # match: )a result: ) * a
+ '
|
([
a
-
z
])
\
s
*
([
a
-
z
]
+
)
' # match: ab result: a * b
+ '
|
([
0
-
9
])
\
s
*
([
a
-
z
])
' # match: 4a result: 4 * a
+ '
|
([
a
-
z
])
\
s
*
([
0
-
9
])
' # match: a4 result: a ^ 4
+ '
|
([
0
-
9
])
\
s
+
([
0
-
9
]))
') # match: 4 4 result: 4 * 4
pattern
=
(
'(?:(
\
))
\
s*(
\
()
'
# )( -> ) * (
+ '
|
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z0
-
9
])
\
s
*
(
\
()
' # a( -> a * (
+ '
|
(
\
))
\
s
*
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z0
-
9
])
' # )a -> ) * a
+ '
|
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z
])
\
s
*
'
+'
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z
]
+
)
' # ab -> a * b
+ '
|
([
0
-
9
])
\
s
*
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z
])
' # 4a -> 4 * a
+ '
|
([
\
x00
-
\
x09
\
x0b
-
\
x19a
-
z
])
\
s
*
([
0
-
9
])
' # a4 -> a ^ 4
+ '
|
([
0
-
9
])
\
s
+
([
0
-
9
]))
' # 4 4 -> 4 * 4
)
def preprocess_data(match):
left, right = filter(None, match.groups())
# Filter words (otherwise they will be preprocessed as well)
if left + right in Parser.words:
return left + right
# Make sure there are no multiplication and exponentiation signs
# inserted between a function and its argument(s): "sin x" should
# not be written as "sin*x", because that is bogus.
if ord(left) <= 0x9 or 0x0b <= ord(left) <= 0x19:
return left + '
' + right
# If all characters on the right are numbers. e.g. "a4", the
# expression implies exponentiation. Make sure ")4" is not
...
...
@@ -180,18 +188,20 @@ class Parser(BisonParser):
data_before
=
data
# Iteratively replace all matches.
while
True
:
data_after
=
re
.
sub
(
pattern
,
preprocess_data
,
data
)
i
=
0
if
data
==
data_after
:
break
while
i
<
len
(
data
):
data
=
data
[:
i
]
+
re
.
sub
(
pattern
,
preprocess_data
,
data
[
i
:])
i
+=
1
data
=
data_after
# Replace escape sequences with original keywords.
for
i
,
keyword
in
enumerate
(
Parser
.
words
):
data
=
data
.
replace
(
chr
(
i
),
keyword
)
if
self
.
verbose
and
data_before
!=
data
_after
:
# pragma: nocover
if
self
.
verbose
and
data_before
!=
data
:
# pragma: nocover
print
'hook_read_after() modified the input data:'
print
'before:'
,
repr
(
data_before
)
print
'after :'
,
repr
(
data
_after
)
print
'after :'
,
repr
(
data
)
return
data
...
...
tests/test_parser.py
View file @
6503a97a
...
...
@@ -50,7 +50,8 @@ class TestParser(unittest.TestCase):
root
,
x
=
tree
(
'sin x, x'
)
self
.
assertEqual
(
root
,
sin
(
x
))
self
.
assertEqual
(
tree
(
'sin x ^ 2'
),
sin
(
x
)
**
2
)
#FIXME: self.assertEqual(tree('sin x ^ 2'), sin(x ** 2))
self
.
assertEqual
(
tree
(
'sin 2 x'
),
sin
(
2
)
*
x
)
self
.
assertEqual
(
tree
(
'sin(x) ^ 2'
),
sin
(
x
)
**
2
)
self
.
assertEqual
(
tree
(
'sin (x) ^ 2'
),
sin
(
x
)
**
2
)
self
.
assertEqual
(
tree
(
'sin(x ^ 2)'
),
sin
(
x
**
2
))
...
...
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