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Merge branch 'master' of github.com:taddeus/licenseplates

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Richard Torenvliet 14 ani în urmă
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@@ -15,9 +15,9 @@
 \maketitle
 \maketitle
 
 
 \section*{Project members}
 \section*{Project members}
-Gijs van der Voort\\
-Raichard Torenvliet\\
-Jayke Meijer\\
+Gijs van der Voort \\
+Richard Torenvliet \\
+Jayke Meijer \\
 Tadde\"us Kroes\\
 Tadde\"us Kroes\\
 Fabi\"en Tesselaar
 Fabi\"en Tesselaar
 
 
@@ -45,38 +45,60 @@ in classifying characters on a license plate.
 In short our program must be able to do the following:
 In short our program must be able to do the following:
 
 
 \begin{enumerate}
 \begin{enumerate}
-    \item Extracting characters using the location points in the xml file.
+    \item Extract characters using the location points in the xml file.
     \item Reduce noise where possible to ensure maximum readability.
     \item Reduce noise where possible to ensure maximum readability.
-    \item Transforming a character to a normal form.
-    \item Creating a local binary pattern histogram vector.
-    \item Matching the found vector with a learning set.
-    \item And finally it has to check results with a real data set.
+    \item Transform a character to a normal form.
+    \item Create a local binary pattern histogram vector.
+    \item Recognize the character value of a vector using a classifier.
+    \item Determine the performance of the classifier with a given test set.
 \end{enumerate}
 \end{enumerate}
 
 
 \section{Language of choice}
 \section{Language of choice}
 
 
 The actual purpose of this project is to check if LBP is capable of recognizing
 The actual purpose of this project is to check if LBP is capable of recognizing
-license plate characters. We knew the LBP implementation would be pretty
-simple. Thus an advantage had to be its speed compared with other license plate
-recognition implementations, but the uncertainty of whether we could get some
-results made us pick Python. We felt Python would not restrict us as much in
-assigning tasks to each member of the group. In addition, when using the
-correct modules to handle images, Python can be decent in speed.
+license plate characters. Since the LBP algorithm is fairly simple to
+implement, it should have a good performance in comparison to other license
+plate recognition implementations if implemented in C. However, we decided to
+focus on functionality rather than speed. Therefore, we picked Python. We felt
+Python would not restrict us as much in assigning tasks to each member of the
+group. In addition, when using the correct modules to handle images, Python can
+be decent in speed.
 
 
 \section{Theory}
 \section{Theory}
 
 
 Now we know what our program has to be capable of, we can start with the
 Now we know what our program has to be capable of, we can start with the
-defining what problems we have and how we want to solve these.
+defining the problems we have and how we are planning to solve these.
 
 
-\subsection{Extracting a letter and resizing it}
+\subsection{Extracting a character and resizing it}
+
+We need to extract a character from a photo made of a car. We do not have to
+find where in this image the characters are, since this is provided in an XML
+file with our dataset.
+
+Once we have extracted the points from this XML file, we need to get this
+character from the image. For the nature of the Local Binary Pattern algorithm,
+we want a margin around the character. However, the points stored in the XML
+file are chosen in such a fashion, that the character would be cut out exactly.
+Therefore, we choose to take points that are slightly outside of the given
+points.
+
+When we have the points we want, we use a perspective transformation to get
+an exact image of the character.
+
+The final step is to resize this image in such a fashion, that the stroke
+of the character is more or less equal in each image. We do this by setting
+the height to a standard size, since each character has the same height on a
+license plate. We retain the height-width ratio, so we do not end up with
+characters that are different than other examples of the same character,
+because the image got stretched, which would of course be a bad thing for
+the classification.
 
 
-Rewrite this section once we have implemented this properly.
 
 
 \subsection{Transformation}
 \subsection{Transformation}
 
 
 A simple perspective transformation will be sufficient to transform and resize
 A simple perspective transformation will be sufficient to transform and resize
 the characters to a normalized format. The corner positions of characters in
 the characters to a normalized format. The corner positions of characters in
-the dataset are supplied together with the dataset.
+the dataset are provided together with the dataset.
 
 
 \subsection{Reducing noise}
 \subsection{Reducing noise}
 
 
@@ -92,51 +114,53 @@ part of the license plate remains readable.
 
 
 \subsection{Local binary patterns}
 \subsection{Local binary patterns}
 Once we have separate digits and characters, we intent to use Local Binary
 Once we have separate digits and characters, we intent to use Local Binary
-Patterns (Ojala, Pietikäinen \& Harwood, 1994) to determine what character
-or digit we are dealing with. Local Binary
-Patterns are a way to classify a texture based on the distribution of edge
-directions in the image. Since letters on a license plate consist mainly of
-straight lines and simple curves, LBP should be suited to identify these.
+Patterns (Ojala, Pietikäinen \& Harwood, 1994) to determine what character or
+digit we are dealing with. Local Binary Patterns are a way to classify a
+texture based on the distribution of edge directions in the image. Since
+letters on a license plate consist mainly of straight lines and simple curves,
+LBP should be suited to identify these.
 
 
 \subsubsection{LBP Algorithm}
 \subsubsection{LBP Algorithm}
 The LBP algorithm that we implemented can use a variety of neighbourhoods,
 The LBP algorithm that we implemented can use a variety of neighbourhoods,
-including the same square pattern that is introduced by Ojala et al (1994),
-and a circular form as presented by Wikipedia.
-\begin{itemize}
+including the same square pattern that is introduced by Ojala et al (1994), and
+a circular form as presented by Wikipedia.
+
+\begin{enumerate}
+
 \item Determine the size of the square where the local patterns are being
 \item Determine the size of the square where the local patterns are being
 registered. For explanation purposes let the square be 3 x 3. \\
 registered. For explanation purposes let the square be 3 x 3. \\
-\item The grayscale value of the middle pixel is used as threshold. Every
-value of the pixel around the middle pixel is evaluated. If it's value is
-greater than the threshold it will be become a one else a zero.
+\item The grayscale value of the center pixel is used as threshold. Every value
+of the pixel around the center pixel is evaluated. If it's value is greater
+than the threshold it will be become a one, otherwise it will be a zero.
 
 
 \begin{figure}[H]
 \begin{figure}[H]
-\center
-\includegraphics[scale=0.5]{lbp.png}
-\caption{LBP 3 x 3 (Pietik\"ainen, Hadid, Zhao \& Ahonen (2011))}
+    \center
+    \includegraphics[scale=0.5]{lbp.png}
+    \caption{LBP 3 x 3 (Pietik\"ainen, Hadid, Zhao \& Ahonen (2011))}
 \end{figure}
 \end{figure}
 
 
-Notice that the pattern will be come of the form 01001110. This is done when a
-the value of the evaluated pixel is greater than the threshold, shift the bit
-by the n(with i=i$_{th}$ pixel evaluated, starting with $i=0$).
+The pattern will be an 8-bit integer. This is accomplished by shifting the
+boolean value of each comparison one to seven places to the left.
 
 
-This results in a mathematical expression:
+This results in the following mathematical expression:
 
 
-Let I($x_i, y_i$) an Image with grayscale values and $g_n$ the grayscale value
-of the pixel $(x_i, y_i)$. Also let $s(g_i, g_c)$ (see below) with $g_c$ =
-grayscale value of the center pixel and $g_i$ the grayscale value of the pixel
-to be evaluated.
+Let I($x_i, y_i$) be a grayscale Image and $g_n$ the value of the pixel $(x_i,
+y_i)$. Also let $s(g_i, g_c)$ (see below) with $g_c$ being the value of the
+center pixel and $g_i$ the grayscale value of the pixel to be evaluated.
 
 
 $$
 $$
-  s(g_i, g_c) = \left\{
-  \begin{array}{l l}
-    1 & \quad \text{if $g_i$ $\geq$ $g_c$}\\
-    0 & \quad \text{if $g_i$ $<$ $g_c$}\\
-  \end{array} \right.
+    s(g_i, g_c) = \left \{
+    \begin{array}{l l}
+        1 & \quad \text{if $g_i$ $\geq$ $g_c$}\\
+        0 & \quad \text{if $g_i$ $<$ $g_c$}\\
+    \end{array} \right.
 $$
 $$
 
 
-$$LBP_{n, g_c = (x_c, y_c)} = \sum\limits_{i=0}^{n-1} s(g_i, g_c)^{2i} $$
+$$LBP_{n, g_c = (x_c, y_c)} = \sum\limits_{i=0}^{n-1} s(g_i, g_c) \cdot 2^i$$
 
 
-The outcome of this operations will be a binary pattern.
+The outcome of this operations will be a binary pattern. Note that the
+mathematical expression has the same effect as the bit shifting operation that
+we defined earlier.
 
 
 \item Given this pattern, the next step is to divide the pattern in cells. The
 \item Given this pattern, the next step is to divide the pattern in cells. The
 amount of cells depends on the quality of the result, so trial and error is in
 amount of cells depends on the quality of the result, so trial and error is in
@@ -145,23 +169,23 @@ order. Starting with dividing the pattern in to cells of size 16.
 \item Compute a histogram for each cell.
 \item Compute a histogram for each cell.
 
 
 \begin{figure}[H]
 \begin{figure}[H]
-\center
-\includegraphics[scale=0.7]{cells.png}
-\caption{Divide in cells(Pietik\"ainen et all (2011))}
+    \center
+    \includegraphics[scale=0.7]{cells.png}
+    \caption{Divide in cells(Pietik\"ainen et all (2011))}
 \end{figure}
 \end{figure}
 
 
 \item Consider every histogram as a vector element and concatenate these. The
 \item Consider every histogram as a vector element and concatenate these. The
 result is a feature vector of the image.
 result is a feature vector of the image.
 
 
-\item Feed these vectors to a support vector machine. This will ''learn'' which
-vector indicates what vector is which character.
+\item Feed these vectors to a support vector machine. The SVM will ``learn''
+which vectors to associate with a character.
 
 
-\end{itemize}
+\end{enumerate}
 
 
 To our knowledge, LBP has yet not been used in this manner before. Therefore,
 To our knowledge, LBP has yet not been used in this manner before. Therefore,
 it will be the first thing to implement, to see if it lives up to the
 it will be the first thing to implement, to see if it lives up to the
-expectations. When the proof of concept is there, it can be used in a final
-program.
+expectations. When the proof of concept is there, it can be used in a final,
+more efficient program.
 
 
 Later we will show that taking a histogram over the entire image (basically
 Later we will show that taking a histogram over the entire image (basically
 working with just one cell) gives us the best results.
 working with just one cell) gives us the best results.
@@ -169,19 +193,19 @@ working with just one cell) gives us the best results.
 \subsection{Matching the database}
 \subsection{Matching the database}
 
 
 Given the LBP of a character, a Support Vector Machine can be used to classify
 Given the LBP of a character, a Support Vector Machine can be used to classify
-the character to a character in a learning set. The SVM uses a concatenation
-of each cell in an image as a feature vector (in the case we check the entire
-image no concatenation has to be done of course. The SVM can be trained with a
-subset of the given dataset called the ''Learning set''. Once trained, the
-entire classifier can be saved as a Pickle object\footnote{See
+the character to a character in a learning set. The SVM uses the concatenation
+of the histograms of all cells in an image as a feature vector (in the case we
+check the entire image no concatenation has to be done of course. The SVM can
+be trained with a subset of the given dataset called the ``learning set''. Once
+trained, the entire classifier can be saved as a Pickle object\footnote{See
 \url{http://docs.python.org/library/pickle.html}} for later usage.
 \url{http://docs.python.org/library/pickle.html}} for later usage.
 In our case the support vector machine uses a radial gauss kernel function. The
 In our case the support vector machine uses a radial gauss kernel function. The
  SVM finds a seperating hyperplane with minimum margins.
  SVM finds a seperating hyperplane with minimum margins.
 
 
 \section{Implementation}
 \section{Implementation}
 
 
-In this section we will describe our implementations in more detail, explaining
-choices we made.
+In this section we will describe our implementation in more detail, explaining
+the choices we made in the process.
 
 
 \subsection{Character retrieval}
 \subsection{Character retrieval}
 
 
@@ -192,7 +216,7 @@ stored in XML files. So, the first step is to read these XML files.
 
 
 \paragraph*{XML reader}
 \paragraph*{XML reader}
 
 
-The XML reader will return a 'license plate' object when given an XML file. The
+The XML reader will return a `license plate' object when given an XML file. The
 licence plate holds a list of, up to six, NormalizedImage characters and from
 licence plate holds a list of, up to six, NormalizedImage characters and from
 which country the plate is from. The reader is currently assuming the XML file
 which country the plate is from. The reader is currently assuming the XML file
 and image name are corresponding, since this was the case for the given
 and image name are corresponding, since this was the case for the given
@@ -239,8 +263,8 @@ any unwanted difference in color from the surrounding pixels.
 \paragraph*{Camera noise and small amounts of dirt}
 \paragraph*{Camera noise and small amounts of dirt}
 The dirt on the license plate can be of different sizes. We can reduce the
 The dirt on the license plate can be of different sizes. We can reduce the
 smaller amounts of dirt in the same way as we reduce normal noise, by applying
 smaller amounts of dirt in the same way as we reduce normal noise, by applying
-a Gaussian blur to the image. This is the next step in our program.\\
-\\
+a Gaussian blur to the image. This is the next step in our program.
+
 The Gaussian filter we use comes from the \texttt{scipy.ndimage} module. We use
 The Gaussian filter we use comes from the \texttt{scipy.ndimage} module. We use
 this function instead of our own function, because the standard functions are
 this function instead of our own function, because the standard functions are
 most likely more optimized then our own implementation, and speed is an
 most likely more optimized then our own implementation, and speed is an
@@ -249,7 +273,7 @@ important factor in this application.
 \paragraph*{Larger amounts of dirt}
 \paragraph*{Larger amounts of dirt}
 Larger amounts of dirt are not going to be resolved by using a Gaussian filter.
 Larger amounts of dirt are not going to be resolved by using a Gaussian filter.
 We rely on one of the characteristics of the Local Binary Pattern, only looking
 We rely on one of the characteristics of the Local Binary Pattern, only looking
-at the difference between two pixels, to take care of these problems.\\
+at the difference between two pixels, to take care of these problems. \\
 Because there will probably always be a difference between the characters and
 Because there will probably always be a difference between the characters and
 the dirt, and the fact that the characters are very black, the shape of the
 the dirt, and the fact that the characters are very black, the shape of the
 characters will still be conserved in the LBP, even if there is dirt
 characters will still be conserved in the LBP, even if there is dirt
@@ -269,8 +293,8 @@ tried the following neighbourhoods:
 
 
 We name these neighbourhoods respectively (8,3)-, (8,5)- and
 We name these neighbourhoods respectively (8,3)-, (8,5)- and
 (12,5)-neighbourhoods, after the number of points we use and the diameter
 (12,5)-neighbourhoods, after the number of points we use and the diameter
-of the `circle´ on which these points lay.\\
-\\
+of the `circle´ on which these points lay.
+
 We chose these neighbourhoods to prevent having to use interpolation, which
 We chose these neighbourhoods to prevent having to use interpolation, which
 would add a computational step, thus making the code execute slower. In the
 would add a computational step, thus making the code execute slower. In the
 next section we will describe what the best neighbourhood was.
 next section we will describe what the best neighbourhood was.
@@ -302,22 +326,21 @@ increasing our performance, so we only have one histogram to feed to the SVM.
 \subsection{Classification}
 \subsection{Classification}
 
 
 For the classification, we use a standard Python Support Vector Machine,
 For the classification, we use a standard Python Support Vector Machine,
-\texttt{libsvm}. This is a often used SVM, and should allow us to simply feed
-the data from the LBP and Feature Vector steps into the SVM and receive
-results.\\
-\\
-Using a SVM has two steps. First you have to train the SVM, and then you can
-use it to classify data. The training step takes a lot of time, so luckily
-\texttt{libsvm} offers us an opportunity to save a trained SVM. This means,
-you do not have to train the SVM every time.\\
-\\
+\texttt{libsvm}. This is an often used SVM, and should allow us to simply feed
+data from the LBP and Feature Vector steps into the SVM and receive results.
+
+Using a SVM has two steps. First, the SVM has to be trained, and then it can be
+used to classify data. The training step takes a lot of time, but luckily
+\texttt{libsvm} offers us an opportunity to save a trained SVM. This means that
+the SVM only has to be changed once.
+
 We have decided to only include a character in the system if the SVM can be
 We have decided to only include a character in the system if the SVM can be
-trained with at least 70 examples. This is done automatically, by splitting
-the data set in a trainingset and a testset, where the first 70 examples of
-a character are added to the trainingset, and all the following examples are
-added to the testset. Therefore, if there are not enough examples, all
-available examples end up in the trainingset, and non of these characters
-end up in the testset, thus they do not decrease our score. However, if this
+trained with at least 70 examples. This is done automatically, by splitting the
+data set in a learning set and a test set, where the first 70 examples of a
+character are added to the learning set, and all the following examples are
+added to the test set. Therefore, if there are not enough examples, all
+available examples end up in the learning set, and non of these characters end
+up in the test set, thus they do not decrease our score. However, if this
 character later does get offered to the system, the training is as good as
 character later does get offered to the system, the training is as good as
 possible, since it is trained with all available characters.
 possible, since it is trained with all available characters.
 
 
@@ -326,15 +349,19 @@ possible, since it is trained with all available characters.
 In order to work with the code, we wrote a number of scripts. Each of these
 In order to work with the code, we wrote a number of scripts. Each of these
 scripts is named here and a description is given on what the script does.
 scripts is named here and a description is given on what the script does.
 
 
-\subsection*{\texttt{find\_svm\_params.py}}
+\subsection*{\texttt{create\_characters.py}}
+
 
 
 
 
+\subsection*{\texttt{create\_classifier.py}}
 
 
-\subsection*{\texttt{LearningSetGenerator.py}}
 
 
 
 
+\subsection*{\texttt{find\_svm\_params.py}}
+
 
 
-\subsection*{\texttt{load\_characters.py}}
+
+\subsection*{\texttt{generate\_learning\_set.py}}
 
 
 
 
 
 
@@ -345,6 +372,7 @@ scripts is named here and a description is given on what the script does.
 \subsection*{\texttt{run\_classifier.py}}
 \subsection*{\texttt{run\_classifier.py}}
 
 
 
 
+
 \section{Finding parameters}
 \section{Finding parameters}
 
 
 Now that we have a functioning system, we need to tune it to work properly for
 Now that we have a functioning system, we need to tune it to work properly for
@@ -362,8 +390,8 @@ available. These parameters are:\\
 	$\gamma$			& Parameter for the Radial kernel used in the SVM.\\
 	$\gamma$			& Parameter for the Radial kernel used in the SVM.\\
 	$c$					& The soft margin of the SVM. Allows how much training
 	$c$					& The soft margin of the SVM. Allows how much training
 						  errors are accepted.\\
 						  errors are accepted.\\
-\end{tabular}\\
-\\
+\end{tabular}
+
 For each of these parameters, we will describe how we searched for a good
 For each of these parameters, we will describe how we searched for a good
 value, and what value we decided on.
 value, and what value we decided on.
 
 
@@ -371,8 +399,8 @@ value, and what value we decided on.
 
 
 The first parameter to decide on, is the $\sigma$ used in the Gaussian blur. To
 The first parameter to decide on, is the $\sigma$ used in the Gaussian blur. To
 find this parameter, we tested a few values, by trying them and checking the
 find this parameter, we tested a few values, by trying them and checking the
-results. It turned out that the best value was $\sigma = 1.4$.\\
-\\
+results. It turned out that the best value was $\sigma = 1.4$.
+
 Theoretically, this can be explained as follows. The filter has width of
 Theoretically, this can be explained as follows. The filter has width of
 $6 * \sigma = 6 * 1.4 = 8.4$ pixels. The width of a `stroke' in a character is,
 $6 * \sigma = 6 * 1.4 = 8.4$ pixels. The width of a `stroke' in a character is,
 after our resize operations, around 8 pixels. This means, our filter `matches'
 after our resize operations, around 8 pixels. This means, our filter `matches'
@@ -388,13 +416,13 @@ classification less affected by relative movement of a character compared to
 those in the learning set, since the important structure will be more likely to
 those in the learning set, since the important structure will be more likely to
 remain in the same cell. However, if the cell size is too big, there will not
 remain in the same cell. However, if the cell size is too big, there will not
 be enough cells to properly describe the different areas of the character, and
 be enough cells to properly describe the different areas of the character, and
-the feature vectors will not have enough elements.\\
-\\
+the feature vectors will not have enough elements.
+
 In order to find this parameter, we used a trial-and-error technique on a few
 In order to find this parameter, we used a trial-and-error technique on a few
 cell sizes. During this testing, we discovered that a lot better score was
 cell sizes. During this testing, we discovered that a lot better score was
 reached when we take the histogram over the entire image, so with a single
 reached when we take the histogram over the entire image, so with a single
-cell. Therefore, we decided to work without cells.\\
-\\
+cell. Therefore, we decided to work without cells.
+
 A reason we can think of why using one cell works best is that the size of a
 A reason we can think of why using one cell works best is that the size of a
 single character on a license plate in the provided dataset is very small.
 single character on a license plate in the provided dataset is very small.
 That means that when dividing it into cells, these cells become simply too
 That means that when dividing it into cells, these cells become simply too
@@ -423,17 +451,17 @@ exact each element in the learning set should be taken. A large soft margin
 means that an element in the learning set that accidentally has a completely
 means that an element in the learning set that accidentally has a completely
 different feature vector than expected, due to noise for example, is not taken
 different feature vector than expected, due to noise for example, is not taken
 into account. If the soft margin is very small, then almost all vectors will be
 into account. If the soft margin is very small, then almost all vectors will be
-taken into account, unless they differ extreme amounts.\\
+taken into account, unless they differ extreme amounts. \\
 $\gamma$ is a variable that determines the size of the radial kernel, and as
 $\gamma$ is a variable that determines the size of the radial kernel, and as
-such determines how steep the difference between two classes can be.\\
-\\
+such determines how steep the difference between two classes can be.
+
 Since these parameters both influence the SVM, we need to find the best
 Since these parameters both influence the SVM, we need to find the best
 combination of values. To do this, we perform a so-called grid-search. A
 combination of values. To do this, we perform a so-called grid-search. A
 grid-search takes exponentially growing sequences for each parameter, and
 grid-search takes exponentially growing sequences for each parameter, and
 checks for each combination of values what the score is. The combination with
 checks for each combination of values what the score is. The combination with
 the highest score is then used as our parameters, and the entire SVM will be
 the highest score is then used as our parameters, and the entire SVM will be
-trained using those parameters.\\
-\\
+trained using those parameters.
+
 The results of this grid-search are shown in the following table. The values
 The results of this grid-search are shown in the following table. The values
 in the table are rounded percentages, for easy displaying.
 in the table are rounded percentages, for easy displaying.
 
 
@@ -481,15 +509,15 @@ Of course, it is vital that the recognition of a license plate is correct,
 almost correct is not good enough here. Therefore, we have to get the highest
 almost correct is not good enough here. Therefore, we have to get the highest
 accuracy score we possibly can.\\
 accuracy score we possibly can.\\
 \\ According to Wikipedia \cite{wikiplate}
 \\ According to Wikipedia \cite{wikiplate}
-commercial license plate recognition software score about $90\%$ to $94\%$,
-under optimal conditions and with modern equipment.\\
-\\
+accuracy score we possibly can. commercial license plate recognition software
+score about $90\%$ to $94\%$, under optimal conditions and with modern equipment.
+
 Our program scores an average of $93\%$. However, this is for a single
 Our program scores an average of $93\%$. However, this is for a single
 character. That means that a full license plate should theoretically
 character. That means that a full license plate should theoretically
 get a score of $0.93^6 = 0.647$, so $64.7\%$. That is not particularly
 get a score of $0.93^6 = 0.647$, so $64.7\%$. That is not particularly
 good compared to the commercial ones. However, our focus was on getting
 good compared to the commercial ones. However, our focus was on getting
-good scores per character, and $93\%$ seems to be a fairly good result.\\
-\\
+good scores per character, and $93\%$ seems to be a fairly good result.
+
 Possibilities for improvement of this score would be more extensive
 Possibilities for improvement of this score would be more extensive
 grid-searches, finding more exact values for $c$ and $\gamma$, more tests
 grid-searches, finding more exact values for $c$ and $\gamma$, more tests
 for finding $\sigma$ and more experiments on the size and shape of the
 for finding $\sigma$ and more experiments on the size and shape of the
@@ -502,20 +530,20 @@ can be a lot of cars passing a camera in a short time, especially on a highway.
 Therefore, we measured how well our program performed in terms of speed. We
 Therefore, we measured how well our program performed in terms of speed. We
 measure the time used to classify a license plate, not the training of the
 measure the time used to classify a license plate, not the training of the
 dataset, since that can be done offline, and speed is not a primary necessity
 dataset, since that can be done offline, and speed is not a primary necessity
-there.\\
-\\
+there.
+
 The speed of a classification turned out to be reasonably good. We time between
 The speed of a classification turned out to be reasonably good. We time between
 the moment a character has been 'cut out' of the image, so we have a exact
 the moment a character has been 'cut out' of the image, so we have a exact
 image of a character, to the moment where the SVM tells us what character it
 image of a character, to the moment where the SVM tells us what character it
 is. This time is on average $65$ ms. That means that this
 is. This time is on average $65$ ms. That means that this
 technique (tested on an AMD Phenom II X4 955 CPU running at 3.2 GHz)
 technique (tested on an AMD Phenom II X4 955 CPU running at 3.2 GHz)
-can identify 15 characters per second.\\
-\\
+can identify 15 characters per second.
+
 This is not spectacular considering the amount of calculating power this CPU
 This is not spectacular considering the amount of calculating power this CPU
 can offer, but it is still fairly reasonable. Of course, this program is
 can offer, but it is still fairly reasonable. Of course, this program is
 written in Python, and is therefore not nearly as optimized as would be
 written in Python, and is therefore not nearly as optimized as would be
-possible when written in a low-level language.\\
-\\
+possible when written in a low-level language.
+
 Another performance gain is by using one of the other two neighbourhoods.
 Another performance gain is by using one of the other two neighbourhoods.
 Since these have 8 points instead of 12 points, this increases performance
 Since these have 8 points instead of 12 points, this increases performance
 drastically, but at the cost of accuracy. With the (8,5)-neighbourhood
 drastically, but at the cost of accuracy. With the (8,5)-neighbourhood
@@ -528,12 +556,12 @@ is not advisable to use.
 
 
 In the end it turns out that using Local Binary Patterns is a promising
 In the end it turns out that using Local Binary Patterns is a promising
 technique for License Plate Recognition. It seems to be relatively indifferent
 technique for License Plate Recognition. It seems to be relatively indifferent
-for the amount of dirt on license plates and different fonts on these plates.\\
-\\
+for the amount of dirt on license plates and different fonts on these plates.
+
 The performance speed wise is fairly good, when using a fast machine. However,
 The performance speed wise is fairly good, when using a fast machine. However,
 this is written in Python, which means it is not as efficient as it could be
 this is written in Python, which means it is not as efficient as it could be
 when using a low-level languages.
 when using a low-level languages.
-\\
+
 We believe that with further experimentation and development, LBP's can
 We believe that with further experimentation and development, LBP's can
 absolutely be used as a good license plate recognition method.
 absolutely be used as a good license plate recognition method.
 
 
@@ -549,15 +577,18 @@ were and whether we were able to find a proper solution for them.
 
 
 We did experience a number of problems with the provided dataset. A number of
 We did experience a number of problems with the provided dataset. A number of
 these are problems to be expected in a real world problem, but which make
 these are problems to be expected in a real world problem, but which make
-development harder. Others are more elemental problems.\\
+development harder. Others are more elemental problems.
+
 The first problem was that the dataset contains a lot of license plates which
 The first problem was that the dataset contains a lot of license plates which
 are problematic to read, due to excessive amounts of dirt on them. Of course,
 are problematic to read, due to excessive amounts of dirt on them. Of course,
 this is something you would encounter in the real situation, but it made it
 this is something you would encounter in the real situation, but it made it
-hard for us to see whether there was a coding error or just a bad example.\\
+hard for us to see whether there was a coding error or just a bad example.
+
 Another problem was that there were license plates of several countries in
 Another problem was that there were license plates of several countries in
 the dataset. Each of these countries has it own font, which also makes it
 the dataset. Each of these countries has it own font, which also makes it
 hard to identify these plates, unless there are a lot of these plates in the
 hard to identify these plates, unless there are a lot of these plates in the
-learning set.\\
+learning set.
+
 A problem that is more elemental is that some of the characters in the dataset
 A problem that is more elemental is that some of the characters in the dataset
 are not properly classified. This is of course very problematic, both for
 are not properly classified. This is of course very problematic, both for
 training the SVM as for checking the performance. This meant we had to check
 training the SVM as for checking the performance. This meant we had to check
@@ -579,6 +610,7 @@ every team member was up-to-date and could start figuring out which part of the
 implementation was most suited to be done by one individually or in a pair.
 implementation was most suited to be done by one individually or in a pair.
 
 
 \subsubsection*{Who did what}
 \subsubsection*{Who did what}
+
 Gijs created the basic classes we could use and helped everyone by keeping
 Gijs created the basic classes we could use and helped everyone by keeping
 track of what was required to be finished and whom was working on what.
 track of what was required to be finished and whom was working on what.
 Tadde\"us and Jayke were mostly working on the SVM and all kinds of tests
 Tadde\"us and Jayke were mostly working on the SVM and all kinds of tests
@@ -627,7 +659,6 @@ can help in future research to achieve a higher accuracy rate.
 \end{figure}
 \end{figure}
 \end{document}
 \end{document}
 
 
-
 \begin{thebibliography}{9}
 \begin{thebibliography}{9}
 \bibitem{lbp1}
 \bibitem{lbp1}
   Matti Pietik\"ainen, Guoyin Zhao, Abdenour hadid,
   Matti Pietik\"ainen, Guoyin Zhao, Abdenour hadid,
@@ -642,3 +673,14 @@ can help in future research to achieve a higher accuracy rate.
   Retrieved from http://en.wikipedia.org/wiki/Automatic\_number\_plate\_recognition
   Retrieved from http://en.wikipedia.org/wiki/Automatic\_number\_plate\_recognition
 \end{thebibliography}
 \end{thebibliography}
 
 
+\appendix
+
+\section{Faulty Classifications}
+
+\begin{figure}[H]
+    \center
+    \includegraphics[scale=0.5]{faulty.png}
+    \caption{Faulty classifications of characters}
+\end{figure}
+
+\end{document}

BIN
docs/verslag.dvi


+ 0 - 495
docs/verslag.tex

@@ -1,495 +0,0 @@
-\documentclass[a4paper]{article}
-
-\usepackage{amsmath}
-\usepackage{hyperref}
-\usepackage{graphicx}
-
-\title{Using local binary patterns to read license plates in photographs}
-
-% Paragraph indentation
-\setlength{\parindent}{0pt}
-\setlength{\parskip}{1ex plus 0.5ex minus 0.2ex}
-
-\begin{document}
-\maketitle
-
-\section*{Project members}
-Gijs van der Voort\\
-Richard Torenvliet\\
-Jayke Meijer\\
-Tadde\"us Kroes\\
-Fabi\'en Tesselaar
-
-\tableofcontents
-\pagebreak
-
-\setcounter{secnumdepth}{1}
-
-\section{Problem description}
-
-License plates are used for uniquely identifying motorized vehicles and are
-made to be read by humans from great distances and in all kinds of weather
-conditions.
-
-Reading license plates with a computer is much more difficult. Our dataset
-contains photographs of license plates from various angles and distances. This
-means that not only do we have to implement a method to read the actual
-characters, but given the location of the license plate and each individual
-character, we must make sure we transform each character to a standard form. 
-This has to be done or else the local binary patterns will never match!
-
-Determining what character we are looking at will be done by using Local Binary
-Patterns. The main goal of our research is finding out how effective LBP's are
-in classifying characters on a license plate.
-
-In short our program must be able to do the following:
-
-\begin{enumerate}
-    \item Use a perspective transformation to obtain an upfront view of license
-          plate.
-    \item Reduce noise where possible to ensure maximum readability.
-    \item Extracting characters using the location points in the xml file.
-    \item Transforming a character to a normal form.
-    \item Creating a local binary pattern histogram vector.
-    \item Matching the found vector with a learning set.
-    \item And finally it has to check results with a real data set.
-\end{enumerate}
-
-\section{Language of choice}
-
-The actual purpose of this project is to check if LBP is capable of recognizing
-license plate characters. We knew the LBP implementation would be pretty
-simple. Thus an advantage had to be its speed compared with other license plate 
-recognition implementations, but the uncertainity of whether we could get some
-results made us pick Python. We felt Python would not restrict us as much in 
-assigning tasks to each member of the group. In addition, when using the
-correct modules to handle images, Python can be decent in speed.
-
-\section{Implementation}
-
-Now we know what our program has to be capable of, we can start with the
-implementations.
-
-
-\subsection{Transformation}
-
-A simple perspective transformation will be sufficient to transform and resize
-the plate to a normalized format. The corner positions of license plates in the
-dataset are supplied together with the dataset.
-
-\subsection{Extracting a letter}
-
-NO LONGER VALID!
-Because we are already given the locations of the characters, we only need to
-transform those locations using the same perspective transformation used to
-create a front facing license plate. The next step is to transform the
-characters to a normalized manner. The size of the letter W is used as a
-standard to normalize the width of all the characters, because W is the widest
-character of the alphabet. We plan to also normalize the height of characters,
-the best manner for this is still to be determined.
-
-\begin{enumerate}
-    \item Crop the image in such a way that the character precisely fits the
-          image.
-    \item Scale the image to a standard height.
-    \item Extend the image on either the left or right side to a certain width.
-\end{enumerate}
-
-The resulting image will always have the same size, the character contained
-will always be of the same height, and the character will alway be positioned
-at either the left of right side of the image.
-
-\subsection{Reducing noise}
-
-Small amounts of noise will probably be suppressed by usage of a Gaussian
-filter. A real problem occurs in very dirty license plates, where branches and
-dirt over a letter could radically change the local binary pattern. A question
-we can ask ourselves here, is whether we want to concentrate ourselves on these
-exceptional cases. By law, license plates have to be readable. Therefore, we
-will first direct our attention at getting a higher score in the 'regular' test
-set before addressing these cases. Considered the fact that the LBP algorithm
-divides a letter into a lot of cells, there is a good change that a great
-number of cells will still match the learning set, and thus still return the
-correct character as a best match. Therefore, we expect the algorithm to be
-very robust when dealing with noisy images.
-
-\subsection{Local binary patterns}
-Once we have separate digits and characters, we intent to use Local Binary
-Patterns (Ojala, Pietikäinen \& Harwood, 1994) to determine what character
-or digit we are dealing with. Local Binary
-Patterns are a way to classify a texture based on the distribution of edge
-directions in the image. Since letters on a license plate consist mainly of
-straight lines and simple curves, LBP should be suited to identify these.
-
-\subsubsection{LBP Algorithm}
-The LBP algorithm that we implemented is a square variant of LBP, the same
-that is introduced by Ojala et al (1994). Wikipedia presents a different
-form where the pattern is circular, this form is convenient because with
-interpolation you can choose the size of the circle \textbf{and} how many
-neighbours the circle has.
-
-In the literature there are lots of examples where LBP is used for surface
-recognition, facial recognition, human face emotion recoqnition (Pietik\"ainen, Hadid, Zhao \& Ahonen (2011))
-\begin{itemize}
-\item Determine the size of the square where the local patterns are being
-registered. For explanation purposes let the square be 3 x 3. \\
-\item The grayscale value of the middle pixel is used a threshold. Every value
-of the pixel around the middle pixel is evaluated. If it's value is greater
-than the threshold it will be become a one else a zero.
-
-\begin{figure}[h!]
-\center
-\includegraphics[scale=0.5]{lbp.png}
-\caption{LBP 3 x 3 (Pietik\"ainen et all (2011))}
-\end{figure}
-
-Notice that the pattern will be come of the form 01001110. This is done when a
-the value of the evaluated pixel is greater than the threshold, shift the bit
-by the n(with i=i$_{th}$ pixel evaluated, starting with $i=0$).
-
-This results in a mathematical expression:
-
-Let I($x_i, y_i$) an Image with grayscale values and $g_n$ the grayscale value
-of the pixel $(x_i, y_i)$. Also let $s(g_i, g_c)$ (see below) with $g_c$ = grayscale value
-of the center pixel and $g_i$ the grayscale value of the pixel to be evaluated.
-
-$$
-  s(g_i, g_c) = \left\{
-  \begin{array}{l l}
-    1 & \quad \text{if $g_i$ $\geq$ $g_c$}\\
-    0 & \quad \text{if $g_i$ $<$ $g_c$}\\
-  \end{array} \right.
-$$
-
-$$LBP_{n, g_c = (x_c, y_c)} = \sum\limits_{i=0}^{n-1} s(g_i, g_c)^{2i} $$
-
-The outcome of this operations will be a binary pattern.
-
-\item Given this pattern, the next step is to divide the pattern in cells. The
-amount of cells depends on the quality of the result, so trial and error is in
-order. Starting with dividing the pattern in to cells of size 16. 
-
-\item Compute a histogram for each cell.
-
-\begin{figure}[h!]
-\center
-\includegraphics[scale=0.7]{cells.png}
-\caption{Divide in cells(Pietik\"ainen et al. (2011))}
-\end{figure}
-
-\item Consider every histogram as a vector element and concatenate these. The
-result is a feature vector of the image.
-
-\item Feed these vectors to a support vector machine. This will ''learn'' which
-vector indicates what vector is which character. 
-
-\end{itemize}
-
-To our knowledge, LBP has yet not been used in this manner before. Therefore,
-it will be the first thing to implement, to see if it lives up to the
-expectations. When the proof of concept is there, it can be used in the final
-program.
-
-Important to note is that due to the normalization of characters before
-applying LBP. Therefore, no further normalization is needed on the histograms.
-
-Given the LBP of a character, a Support Vector Machine can be used to classify
-the character to a character in a learning set.
-
-\subsection{Matching the database}
-
-Given the LBP of a character, a Support Vector Machine can be used to classify
-the character to a character in a learning set. The SVM uses the collection of
-histograms of an image as a feature vector.  The SVM can be trained with a
-subsection of the given dataset called the ''Learning set''. Once trained, the
-entire classifier can be saved as a Pickle object\footnote{See
-\url{http://docs.python.org/library/pickle.html}} for later usage.
-In our case a support vector machine uses a radial gauss kernel. The SVM finds
-a seperating hyperplane with minimum margins.
-
-
-
-\section{Implementation}
-
-In this section we will describe our implementations in more detail, explaining
-choices we made.
-
-\subsection{Licenseplate retrieval}
-
-In order to retrieve the license plate from the entire image, we need to
-perform a perspective transformation. However, to do this, we need to know the 
-coordinates of the four corners of the licenseplate. For our dataset, this is
-stored in XML files. So, the first step is to read these XML files.
-
-\paragraph*{XML reader}
-
-The XML reader will return a 'license plate' object when given an XML file. The
-licence plate holds a list of, up to six, NormalizedImage characters and from
-which country the plate is from. The reader is currently assuming the XML file
-and image name are corresponding. Since this was the case for the given
-dataset. This can easily be adjusted if required. 
-
-To parse the XML file, the minidom module is used. So the XML file can be
-treated as a tree, where one can search for certain nodes. In each XML
-file it is possible that multiple versions exist, so the first thing the reader
-will do is retrieve the current and most up-to-date version of the plate. The
-reader will only get results from this version.
-
-Now we are only interested in the individual characters so we can skip the
-location of the entire license plate. Each character has 
-a single character value, indicating what someone thought what the letter or
-digit was and four coordinates to create a bounding box. To make things not to
-complicated a Character class and Point class are used. They
-act pretty much as associative lists, but it gives extra freedom on using the
-data. If less then four points have been set the character will not be saved.
-
-When four points have been gathered the data from the actual image is being
-requested. For each corner a small margin is added (around 3 pixels) so that no
-features will be lost and minimum amounts of new features will be introduced by
-noise in the margin. 
-
-In the next section you can read more about the perspective transformation that
-is being done. After the transformation the character can be saved: Converted
-to grayscale, but nothing further. This was used to create a learning set. If
-it doesn't need to be saved as an actual image it will be converted to a
-NormalizedImage. When these actions have been completed for each character the
-license plate is usable in the rest of the code.
-
-\paragraph*{Perspective transformation}
-Once we retrieved the cornerpoints of the license plate, we feed those to a
-module that extracts the (warped) license plate from the original image, and
-creates a new image where the license plate is cut out, and is transformed to a
-rectangle.
-
-\subsection{Noise reduction}
-
-The image contains a lot of noise, both from camera errors due to dark noise 
-etc., as from dirt on the license plate. In this case, noise therefore means 
-any unwanted difference in color from the surrounding pixels.
-
-\paragraph*{Camera noise and small amounts of dirt}
-The dirt on the license plate can be of different sizes. We can reduce the 
-smaller amounts of dirt in the same way as we reduce normal noise, by applying
-a Gaussian blur to the image. This is the next step in our program.\\
-\\
-The Gaussian filter we use comes from the \texttt{scipy.ndimage} module. We use
-this function instead of our own function, because the standard functions are
-most likely more optimized then our own implementation, and speed is an
-important factor in this application.
-
-\paragraph*{Larger amounts of dirt}
-Larger amounts of dirt are not going to be resolved by using a Gaussian filter.
-We rely on one of the characteristics of the Local Binary Pattern, only looking
-at the difference between two pixels, to take care of these problems.\\
-Because there will probably always be a difference between the characters and
-the dirt, and the fact that the characters are very black, the shape of the
-characters will still be conserved in the LBP, even if there is dirt
-surrounding the character.
-
-\subsection{Character retrieval}
-
-The retrieval of the character is done the same as the retrieval of the license
-plate, by using a perspective transformation. The location of the characters on
-the license plate is also available in de XML file, so this is parsed from that
-as well.
-
-\subsection{Creating Local Binary Patterns and feature vector}
-Every pixel is a center pixel and it is also a value to evaluate, but not at the 
-same time. Every pixel is evaluated as shown in the section about the LBP algorithm,
-in a square.  
-The 8 neighbours around that pixel are evaluated. This area can be bigger but this
-form is the generic form of LBP, no interpolation is needed because the pixels adressed
-as neighbours are indeed pixels. 
-
-Take an example where the 
-full square can be evaluated, there are cases where the neighbours are out of 
-bounds. The first to be checked is the pixel in the left 
-bottom corner in the square 3 x 3, with coordinate $(x - 1, y - 1)$ with $g_c$ 
-as center pixel on location $(x, y)$. If the grayscale value of the
-neighbour in the left bottom corner is greater than the grayscale
-value of the center pixel than return true. Bitshift the first bit with 7. The
-outcome is now 1000000. The second neighbour will be bitshifted with 6, and so 
-on. Until we are at 0. The result is a binary pattern of the local point just
-evaluated.
-Now only the edge pixels are a problem, but a simpel check if the location of
-the neighbour is still in the image can resolve this. We simply return false if
-it is.
-
-\paragraph*{Histogram and Feature Vector}
-After all the Local Binary Patterns are created for every pixel. This pattern
-is divided in to cells. The feature vector is the vector of concatenated
-histograms. These histograms are created for cells. These cells are created by
-dividing the \textbf{pattern} in to cells and create a histogram of that. So multiple
-cells are related to one histogram. All the histograms are concatenated and
-feeded to the SVM that will be discussed in the next section, Classification.
-
-\subsection{Classification}
-
-
-\section{Finding parameters}
-
-Now that we have a functioning system, we need to tune it to work properly for
-license plates. This means we need to find the parameters. Throughout the 
-program we have a number of parameters for which no standard choice is
-available. These parameters are:\\
-\\
-\begin{tabular}{l|l}
-	Parameter 			& Description\\
-	\hline
-	$\sigma$  			& The size of the Gaussian blur.\\
-	\emph{cell size}	& The size of a cell for which a histogram of LBPs will
-	                      be generated.\\
-	$\gamma$			& Parameter for the Radial kernel used in the SVM.\\
-	$c$					& The soft margin of the SVM. Allows how much training
-						  errors are accepted.
-\end{tabular}\\
-\\
-For each of these parameters, we will describe how we searched for a good
-value, and what value we decided on.
-
-\subsection{Parameter $\sigma$}
-
-The first parameter to decide on, is the $\sigma$ used in the Gaussian blur. To
-find this parameter, we tested a few values, by checking visually what value
-removed most noise out of the image, while keeping the edges sharp enough to
-work with. By checking in the neighbourhood of the value that performed best,
-we where able to 'zoom in' on what we thought was the best value. It turned out
-that this was $\sigma = ?$.
-
-\subsection{Parameter \emph{cell size}}
-
-The cell size of the Local Binary Patterns determines over what region a
-histogram is made. The trade-off here is that a bigger cell size makes the
-classification less affected by relative movement of a character compared to
-those in the learning set, since the important structure will be more likely to
-remain in the same cell. However, if the cell size is too big, there will not
-be enough cells to properly describe the different areas of the character, and
-the feature vectors will not have enough elements.\\
-\\
-In order to find this parameter, we used a trial-and-error technique on a few
-basic cell sizes, being ?, 16, ?. We found that the best result was reached by
-using ??.
-
-\subsection{Parameters $\gamma$ \& $c$}
-
-The parameters $\gamma$ and $c$ are used for the SVM. $c$ is a standard
-parameter for each type of SVM, called the 'soft margin'. This indicates how
-exact each element in the learning set should be taken. A large soft margin
-means that an element in the learning set that accidentally has a completely
-different feature vector than expected, due to noise for example, is not taken
-into account. If the soft margin is very small, then almost all vectors will be
-taken into account, unless they differ extreme amounts.\\
-$\gamma$ is a variable that determines the size of the radial kernel, and as
-such blablabla.\\
-\\
-Since these parameters both influence the SVM, we need to find the best
-combination of values. To do this, we perform a so-called grid-search. A
-grid-search takes exponentially growing sequences for each parameter, and
-checks for each combination of values what the score is. The combination with
-the highest score is then used as our parameters, and the entire SVM will be
-trained using those parameters.\\
-\\
-We found that the best values for these parameters are $c=?$ and $\gamma =?$.
-
-\section{Results}
-
-The goal was to find out two things with this research: The speed of the
-classification and the accuracy. In this section we will show our findings.
-
-\subsection{Speed}
-
-Recognizing license plates is something that has to be done fast, since there
-can be a lot of cars passing a camera in a short time, especially on a highway.
-Therefore, we measured how well our program performed in terms of speed. We
-measure the time used to classify a license plate, not the training of the
-dataset, since that can be done offline, and speed is not a primary necessity
-there.\\
-\\
-The speed of a classification turned out to be blablabla.
-
-\subsection{Accuracy}
-
-Of course, it is vital that the recognition of a license plate is correct,
-almost correct is not good enough here. Therefore, we have to get the highest
-accuracy score we possibly can.\\
-\\ According to Wikipedia
-\footnote{
-\url{http://en.wikipedia.org/wiki/Automatic_number_plate_recognition}},
-commercial license plate recognition software score about $90\%$ to $94\%$,
-under optimal conditions and with modern equipment. Our program scores an
-average of blablabla.
-
-\section{Difficulties}
-
-During the implementation and testing of the program, we did encounter a
-number of difficulties. In this section we will state what these difficulties
-were and whether we were able to find a proper solution for them.
-
-\subsection*{Dataset}
-
-We did experience a number of problems with the provided dataset. A number of
-these are problems to be expected in a real world problem, but which make
-development harder. Others are more elemental problems.\\
-The first problem was that the dataset contains a lot of license plates which
-are problematic to read, due to excessive amounts of dirt on them. Of course,
-this is something you would encounter in the real situation, but it made it
-hard for us to see whether there was a coding error or just a bad example.\\
-Another problem was that there were license plates of several countries in
-the dataset. Each of these countries has it own font, which also makes it
-hard to identify these plates, unless there are a lot of these plates in the
-learning set.\\
-A problem that is more elemental is that some of the characters in the dataset
-are not properly classified. This is of course very problematic, both for
-training the SVM as for checking the performance. This meant we had to check
-each character whether its description was correct.
-
-\subsection*{SVM}
-
-We also had trouble with the SVM for Python. The standard Python SVM, libsvm,
-had a poor documentation. There was no explanation what so ever on which
-parameter had to be what. This made it a lot harder for us to see what went
-wrong in the program.
-
-\section{Workload distribution}
-
-The first two weeks were team based. Basically the LBP algorithm could be
-implemented in the first hour, while some talked and someone did the typing.
-Some additional 'basics' where created in similar fashion. This ensured that
-every team member was up-to-date and could start figuring out which part of the
-implementation was most suited to be done by one individually or in a pair.
-
-\subsection{Who did what}
-Gijs created the basic classes we could use and helped the rest everyone by 
-keeping track of what required to be finished and whom was working on what. 
-Tadde\"us and Jayke were mostly working on the SVM and all kinds of tests
-whether the histograms were matching and alike. Fabi\"en created the functions
-to read and parse the given xml files with information about the license
-plates. Upon completion all kinds of learning and data sets could be created.
-
-%Richard je moet even toevoegen wat je hebt gedaan :P:P
-%maar miss is dit hele ding wel overbodig Ik dacht dat Rein het zei tijdens
-%gesprek van ik wil weten hoe het ging enzo.
-
-\subsection{How it went}
-
-Sometimes one cannot hear the alarm bell and wake up properly. This however was
-not a big problem as no one was affraid of staying at Science Park a bit longer
-to help out. Further communication usually went through e-mails and replies
-were instantaneous! A crew to remember.
-
-\section{Conclusion}
-
-Awesome
-
-\begin{thebibliography}{9}
-\bibitem{lbp1}
-  Matti Pietik\"ainen, Guoyin Zhao, Abdenour hadid,
-  Timo Ahonen.
-  \emph{Computational Imaging and Vision}.
-  Springer-Verlag, London,
-  1nd Edition,
-  2011.
-\end{thebibliography}
-
-
-\end{document}

+ 3 - 0
src/Character.py

@@ -8,6 +8,8 @@ class Character:
         self.filename = filename
         self.filename = filename
 
 
     def get_single_cell_feature_vector(self, neighbours=5):
     def get_single_cell_feature_vector(self, neighbours=5):
+        """Get the histogram of Local Binary Patterns over this entire
+        image."""
         if hasattr(self, 'feature'):
         if hasattr(self, 'feature'):
             return
             return
 
 
@@ -15,6 +17,7 @@ class Character:
         self.feature = pattern.single_cell_features_vector()
         self.feature = pattern.single_cell_features_vector()
 
 
     def get_feature_vector(self, cell_size=None):
     def get_feature_vector(self, cell_size=None):
+        """Get the concatenated histograms of Local Binary Patterns. """
         pattern = LBP(self.image) if cell_size == None \
         pattern = LBP(self.image) if cell_size == None \
                   else LBP(self.image, cell_size)
                   else LBP(self.image, cell_size)
 
 

+ 1 - 3
src/Classifier.py

@@ -1,12 +1,9 @@
 from svmutil import svm_train, svm_problem, svm_parameter, svm_predict, \
 from svmutil import svm_train, svm_problem, svm_parameter, svm_predict, \
         svm_save_model, svm_load_model, RBF
         svm_save_model, svm_load_model, RBF
 
 
-
 class Classifier:
 class Classifier:
     def __init__(self, c=None, gamma=None, filename=None, neighbours=3, \
     def __init__(self, c=None, gamma=None, filename=None, neighbours=3, \
             verbose=0):
             verbose=0):
-        self.neighbours = neighbours
-
         if filename:
         if filename:
             # If a filename is given, load a model from the given filename
             # If a filename is given, load a model from the given filename
             self.model = svm_load_model(filename)
             self.model = svm_load_model(filename)
@@ -19,6 +16,7 @@ class Classifier:
             self.param.gamma = gamma  # Parameter for radial kernel
             self.param.gamma = gamma  # Parameter for radial kernel
             self.model = None
             self.model = None
 
 
+        self.neighbours = neighbours
         self.verbose = verbose
         self.verbose = verbose
 
 
     def save(self, filename):
     def save(self, filename):

+ 0 - 14
src/GrayscaleImage.py

@@ -22,20 +22,6 @@ class GrayscaleImage:
             for x in xrange(self.data.shape[1]):
             for x in xrange(self.data.shape[1]):
                 yield y, x, self.data[y, x]
                 yield y, x, self.data[y, x]
 
 
-        #self.__i_x = -1
-        #self.__i_y = 0
-        #return self
-
-    #def next(self):
-    #    self.__i_x += 1
-    #    if self.__i_x  == self.width:
-    #        self.__i_x = 0
-    #        self.__i_y += 1
-    #    if self.__i_y == self.height:
-    #        raise StopIteration
-
-    #    return  self.__i_y, self.__i_x, self[self.__i_y, self.__i_x]
-
     def __getitem__(self, position):
     def __getitem__(self, position):
         return self.data[position]
         return self.data[position]
 
 

+ 0 - 4
src/Histogram.py

@@ -6,13 +6,9 @@ class Histogram:
         self.max = max
         self.max = max
 
 
     def add(self, number):
     def add(self, number):
-        #bin_index = self.get_bin_index(number)
-        #self.bins[bin_index] += 1
         self.bins[number] += 1
         self.bins[number] += 1
 
 
     def remove(self, number):
     def remove(self, number):
-        #bin_index = self.get_bin_index(number)
-        #self.bins[bin_index] -= 1
         self.bins[number] -= 1
         self.bins[number] -= 1
 
 
     def get_bin_index(self, number):
     def get_bin_index(self, number):

+ 6 - 4
src/NormalizedCharacterImage.py

@@ -13,14 +13,16 @@ class NormalizedCharacterImage(GrayscaleImage):
         self.blur = blur
         self.blur = blur
         self.gaussian_filter()
         self.gaussian_filter()
 
 
-        self.increase_contrast()
+        #self.increase_contrast()
 
 
         self.height = height
         self.height = height
         self.resize()
         self.resize()
 
 
-    def increase_contrast(self):
-        self.data -= self.data.min()
-        self.data = self.data.astype(float) / self.data.max()
+#    def increase_contrast(self):
+#        """Increase the contrast by performing a grayscale mapping from the 
+#        current maximum and minimum to a range between 0 and 1."""
+#        self.data -= self.data.min()
+#        self.data = self.data.astype(float) / self.data.max()
 
 
     def gaussian_filter(self):
     def gaussian_filter(self):
         GaussianFilter(self.blur).filter(self)
         GaussianFilter(self.blur).filter(self)

+ 1 - 0
src/create_characters.py

@@ -80,6 +80,7 @@ def load_test_set(neighbours, blur_scale, verbose=0):
 
 
 
 
 def generate_sets(neighbours, blur_scale, verbose=0):
 def generate_sets(neighbours, blur_scale, verbose=0):
+    """Split the entire dataset into a trainingset and a testset."""
     suffix = '_%s_%s' % (blur_scale, neighbours)
     suffix = '_%s_%s' % (blur_scale, neighbours)
     learning_set_file = 'learning_set%s.dat' % suffix
     learning_set_file = 'learning_set%s.dat' % suffix
     test_set_file = 'test_set%s.dat' % suffix
     test_set_file = 'test_set%s.dat' % suffix

+ 2 - 2
src/create_classifier.py

@@ -12,8 +12,8 @@ def load_classifier(neighbours, blur_scale, c=None, gamma=None, verbose=0):
         if verbose:
         if verbose:
             print 'Loading classifier...'
             print 'Loading classifier...'
 
 
-        classifier = Classifier(filename=classifier_file, verbose=verbose)
-        classifier.neighbours = neighbours
+        classifier = Classifier(filename=classifier_file, \
+                neighbours=neighbours, verbose=verbose)
     elif c != None and gamma != None:
     elif c != None and gamma != None:
         if verbose:
         if verbose:
             print 'Training new classifier...'
             print 'Training new classifier...'

+ 71 - 91
src/xml_helper_functions.py

@@ -1,21 +1,17 @@
 from os import mkdir
 from os import mkdir
 from os.path import exists
 from os.path import exists
-from pylab import array, zeros, inv, dot, svd, floor
+from pylab import imsave, array, zeros, inv, dot, norm, svd, floor
 from xml.dom.minidom import parse
 from xml.dom.minidom import parse
-from Point import Point
 from Character import Character
 from Character import Character
 from GrayscaleImage import GrayscaleImage
 from GrayscaleImage import GrayscaleImage
 from NormalizedCharacterImage import NormalizedCharacterImage
 from NormalizedCharacterImage import NormalizedCharacterImage
 from LicensePlate import LicensePlate
 from LicensePlate import LicensePlate
 
 
-# sets the entire license plate of an image
-def retrieve_data(image, corners):
-    x0, y0 = corners[0].to_tuple()
-    x1, y1 = corners[1].to_tuple()
-    x2, y2 = corners[2].to_tuple()
-    x3, y3 = corners[3].to_tuple()
+# Gets the character data from a picture with a license plate
+def retrieve_data(plate, corners):
+    x0,y0, x1,y1, x2,y2, x3,y3 = corners
 
 
-    M = int(1.2 * (max(x0, x1, x2, x3) - min(x0, x1, x2, x3)))
+    M = max(x0, x1, x2, x3) - min(x0, x1, x2, x3)
     N = max(y0, y1, y2, y3) - min(y0, y1, y2, y3)
     N = max(y0, y1, y2, y3) - min(y0, y1, y2, y3)
 
 
     matrix = array([
     matrix = array([
@@ -29,7 +25,7 @@ def retrieve_data(image, corners):
       [ 0,  0, 0, x3, y3, 1, -N * x3, -N * y3, -N]
       [ 0,  0, 0, x3, y3, 1, -N * x3, -N * y3, -N]
     ])
     ])
 
 
-    P = inv(get_transformation_matrix(matrix))
+    P = get_transformation_matrix(matrix)
     data = array([zeros(M, float)] * N)
     data = array([zeros(M, float)] * N)
 
 
     for i in range(M):
     for i in range(M):
@@ -38,7 +34,7 @@ def retrieve_data(image, corners):
             or_coor_h = (or_coor[1][0] / or_coor[2][0],
             or_coor_h = (or_coor[1][0] / or_coor[2][0],
                          or_coor[0][0] / or_coor[2][0])
                          or_coor[0][0] / or_coor[2][0])
 
 
-            data[j][i] = pV(image, or_coor_h[0], or_coor_h[1])
+            data[j][i] = pV(plate, or_coor_h[0], or_coor_h[1])
 
 
     return data
     return data
 
 
@@ -50,108 +46,92 @@ def get_transformation_matrix(matrix):
     U, D, V = svd(matrix)
     U, D, V = svd(matrix)
     p = V[8][:]
     p = V[8][:]
 
 
-    return array([
-        [ p[0], p[1], p[2] ],
-        [ p[3], p[4], p[5] ],
-        [ p[6], p[7], p[8] ]
-    ])
+    return inv(array([[p[0],p[1],p[2]], [p[3],p[4],p[5]], [p[6],p[7],p[8]]]))
 
 
 def pV(image, x, y):
 def pV(image, x, y):
     #Get the value of a point (interpolated x, y) in the given image
     #Get the value of a point (interpolated x, y) in the given image
-    if image.in_bounds(x, y):
-        x_low  = floor(x)
-        x_high = floor(x + 1)
-        y_low  = floor(y)
-        y_high = floor(y + 1)
-        x_y    = (x_high - x_low) * (y_high - y_low)
+    if not image.in_bounds(x, y):
+      return 0
 
 
-        a = x_high - x
-        b = y_high - y
-        c = x - x_low
-        d = y - y_low
+    x_low, x_high = floor(x), floor(x+1)
+    y_low, y_high = floor(y), floor(y+1)
+    x_y    = (x_high - x_low) * (y_high - y_low)
 
 
-        return image[x_low,  y_low] / x_y * a * b \
-            + image[x_high,  y_low] / x_y * c * b \
-            + image[x_low , y_high] / x_y * a * d \
-            + image[x_high, y_high] / x_y * c * d
+    a = x_high - x
+    b = y_high - y
+    c = x - x_low
+    d = y - y_low
 
 
-    return 0
+    return image[x_low,  y_low] / x_y * a * b \
+        + image[x_high,  y_low] / x_y * c * b \
+        + image[x_low , y_high] / x_y * a * d \
+        + image[x_high, y_high] / x_y * c * d
 
 
 def xml_to_LicensePlate(filename, save_character=None):
 def xml_to_LicensePlate(filename, save_character=None):
-    image = GrayscaleImage('../images/Images/%s.jpg' % filename)
-    dom   = parse('../images/Infos/%s.info' % filename)
-    result_characters = []
-
-    version = dom.getElementsByTagName("current-version")[0].firstChild.data
-    info    = dom.getElementsByTagName("info")
+    plate   = GrayscaleImage('../images/Images/%s.jpg' % filename)
+    dom     = parse('../images/Infos/%s.info' % filename)
+    country = ''
+    result  = []
+    version = get_node(dom, "current-version")
+    infos   = by_tag(dom, "info")
 
 
-    for i in info:
-        if version == i.getElementsByTagName("version")[0].firstChild.data:
+    for info in infos:
+        if not version == get_node(info, "version"):
+            continue
 
 
-            country = i.getElementsByTagName("identification-letters")[0].firstChild.data
-            temp = i.getElementsByTagName("characters")
+        country = get_node(info, "identification-letters")
+        temp    = by_tag(info, "characters")
 
 
-            if len(temp):
-              characters = temp[0].childNodes
-            else:
-              characters = []
-              break
+        if not temp: # no characters where found in the file
+            break
 
 
-            for i, character in enumerate(characters):
-                if character.nodeName == "character":
-                    value   = character.getElementsByTagName("char")[0].firstChild.data
-                    corners = get_corners(character)
+        characters = temp[0].childNodes
 
 
-                    if not len(corners) == 4:
-                      break
+        for i, char in enumerate(characters):
+            if not char.nodeName == "character":
+              continue
 
 
-                    character_data  = retrieve_data(image, corners)
-                    character_image = NormalizedCharacterImage(data=character_data)
+            value   = get_node(char, "char")
+            corners = get_corners(char)
 
 
-                    result_characters.append(Character(value, corners, character_image, filename))
+            if not len(corners) == 8:
+                break
 
 
-                    if save_character:
-                        single_character = GrayscaleImage(data=character_data)
+            data  = retrieve_data(plate, corners)
+            image = NormalizedCharacterImage(data=data)
+            result.append(Character(value, corners, image, filename))
+        
+            if save_character:
+                character_image = GrayscaleImage(data=data)
+                path       = "../images/LearningSet/%s" % value
+                image_path = "%s/%d_%s.jpg" % (path, i, filename.split('/')[-1])
 
 
-                        path = "../images/LearningSet/%s" % value
-                        image_path = "%s/%d_%s.jpg" % (path, i, filename.split('/')[-1])
+                if not exists(path):
+                  mkdir(path)
 
 
-                        if not exists(path):
-                          mkdir(path)
+                if not exists(image_path):
+                  character_image.save(image_path)
 
 
-                        if not exists(image_path):
-                          single_character.save(image_path)
+    return LicensePlate(country, result)
 
 
-    return LicensePlate(country, result_characters)
-
-def get_corners(dom):
-  nodes = dom.getElementsByTagName("point")
-  corners = []
+def get_node(node, tag):
+    return by_tag(node, tag)[0].firstChild.data
 
 
-  margin_y = 3
-  margin_x = 2
+def by_tag(node, tag):
+    return node.getElementsByTagName(tag)
 
 
-  corners.append(
-    Point(get_coord(nodes[0], "x") - margin_x,
-          get_coord(nodes[0], "y") - margin_y)
-  )
+def get_attr(node, attr):
+  return int(node.getAttribute(attr))
 
 
-  corners.append(
-    Point(get_coord(nodes[1], "x") + margin_x,
-          get_coord(nodes[1], "y") - margin_y)
-  )
-
-  corners.append(
-    Point(get_coord(nodes[2], "x") + margin_x,
-          get_coord(nodes[2], "y") + margin_y)
-  )
-
-  corners.append(
-    Point(get_coord(nodes[3], "x") - margin_x,
-          get_coord(nodes[3], "y") + margin_y)
-  )
+def get_corners(dom):
+    p = by_tag(dom, "point")
 
 
-  return corners
+    # Extra padding
+    y = 3
+    x = 2
 
 
-def get_coord(node, attribute):
-  return int(node.getAttribute(attribute))
+    # return 8 values (x0,y0, .., x3,y3)
+    return get_attr(p[0], "x") - x, get_attr(p[0], "y") - y,\
+           get_attr(p[1], "x") + x, get_attr(p[1], "y") - y,\
+           get_attr(p[2], "x") + x, get_attr(p[2], "y") + y,\
+           get_attr(p[3], "x") - x, get_attr(p[3], "y") + y